Grading Students Hacker Rank Solution with Explanation

Posted by admin August 3, 2022
Grading Students Hacker Rank Solution with Explanation
Grading Students Hacker Rank Solution with Explanation

Grading student hackerrank solution with explanation, first lets see what the problem is :

Grading Students Hacker Rank Problem:

HackerLand University has the following grading policy:

   1. Every student receives a grade in the inclusive range from 1 to 100.
   2. Any grade less than 30 is a failing grade. 

     

Sam is a professor at the university and likes to round each student's grade
 according to these rules:

  1.If the difference between the grade and the next multiple of 5 is less
 than 3 , round up to the next 
multiple of 5.
  2.If the value of grade  is less than 38 , no rounding occurs as the result 
will still be a failing grade.

Examples

  1. grade = 84 round to85 (85 - 84 is less than 3)
  2. grade = 29 do not round (result is less than 40)
  3. grade = do not round (60 - 57 is 3 or higher)

Given the initial value of  grade for each of Sam's n students, write code 
to automate the rounding 
process. 

Function Description

Complete the function gradingStudents in the editor below.

gradingStudents has the following parameter(s):

    int grades[n]: the grades before rounding

Returns

    int[n]: the grades after rounding as appropriate

Input Format

The first line contains a single integer,n , the number of students.
Each line i of the n subsequent lines contains a single integer, grades[i].

Constraints
  
  1<= n < =60
  0 <= grades[i] <= 100

Grading students Hackerrank solution JavaScript:

function gradingStudents(grades) {
   grades.forEach((grade, i) => {
     let  count = 5 - grade % 5;
      if (grade >= 38 && count < 3) 
      {grades[i] += count;
      }  
  });
  return grades;
}

Grading students Hackerrank solution Python:

def gradingStudents(grades):
    for i in range(len(grades)):
        if grades[i] < 38: continue
        diff = grades[i] % 5
        if 5 - diff < 3:
            grades[i] += 5 - diff       
    return grades

Grading students Hackerrank solution C#:

public static List GradingStudents(List grades)
{
    for (int i = 0; i < grades.Count; i++) { int diff = 5 - grades[i] % 5; if (grades[i] 
>= 38 && diff < 3)
            grades[i] += diff;
    } 
    return grades;
}

Explanation of Code:

  1. First, we need to find whether grade is less greater than 38 or not.
  2. Then we need to find if the number on diving by 5 gives a number less than 3 or not using given line 5 – grade[i]  % 5 and made it equal to some temp variable.
  3. If both conditions satisfied then add the temp variable to grades else return the original grades